algebra
posted by Hokoslavia .
use the quadratic formula to solve the equation
4x^27x2=0

Your equation is already in the form ax^2 + bx + c = 0
In your case,
a = 4, b = 7 and c = 2.
The quadratic formula for the solution values of x, which you should memorize or learn to derive, is
x = [b +/ sqrt (b^24ac)]/2a
It would good practice for you to do the final alculation yourself
b^24ac = 81 in this case, and has a square root that is an integer, making the answer rather easy to write down. 
x = b/2a +/ (1/2a)sqrt(b^2  4 a c)
a = 4
b = 7
c = 2
x = 7/8 +/ (1/8) sqrt ( 49 + 32)
x = 7/8 +/ (1/8) sqrt (81)
lucky (9*9)=81
so
x = 7/8 +/ 9/8
x = 16/8 or 2/8 wow, nice polite numbers
so
x = 2 or  1/4