algebra
posted by Hokoslavia .
Identify the vertex and axis of symetry of the parabola. Identify points corresponding to P and Q. on the graph it has P at (2,4) and a point at Q at (1,7). my teacher says the answers were the vertex was (1,3) the Axis of symmtry was X=1 the P is (0,4) and Q is (3,7).. how do you figure out each of those steps? im confused with how to do the whole problem

The P and Q coordinates in your first statement do not agree with the P and Q in your last statement. I would need to see the graph to know what this problem is all about.

I will try to reverse engineer this mess.
(y3) = k (x+1)^2
if the vertex is at (1,3) and x=1 is the axis
put in P at (1,7) impossible because y = 3 when x = 1
so I will try the second pair of points
P at (0,4)
(43) = k (1)^2
so k = 1
so
y  3 = (x+1)^2
try Q at (3,7)
4 = (2)^2
YES
so the parabola with axis of symmetry at x = 1 and vertex at (1,3) can contain the SECOND pair of points P and Q
rewrite in standard form
y = 3 +x^2 + 2 x + 1
y = x^2 + 2 x + 4
I have no idea what the two original points P and Q were. They are on some other curve.
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