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posted by Jon Friday, March 7, 2008 at 1:51pm.
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (x=theta BTW)
(secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) The last steps should be obvious
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