posted by .

i am having a hard time with factoring i have read what is here but am still having trouble can some one help me with the problem s^2-s-6, and y^2-4y-5. these are expressions which either can be factored or are prime. can someone explain how to do these in regular terms.

  • math -

    They factor into (s-3)(s+2) and

    Look at the constant term at the end and see what prime number it can be factored into. In the case of 6 (in the first problem), it can be either 3 and 2, or 6 and 1. Because of the minus sign in front of the 6, you have to have opposite signs on the two numbers that you pick. Also, the sum of the two must be -1 (the coefficient of the middle "s" term). The numbers that meet these requirements are -3 and +2. Hence the factors are (s-3) and (s+2)

    If the coefficent of the "square" term were not 1, the problem gets a bit more complex, but it still comes down to looking for prime number factors of the squared term's coefficient and the constant term, computing the middle term, and a bit of trial and error.

  • math -

    s^2 - s - 6
    What you're looking for is a number that when you multiply it, it equals
    -6 and when you add them it equals -1. these values -6 and -1 are derived from the equation.

    so number could be --> -/+ 3, -/+ 2
    but since there's only one way of getting -1 when you add them. the answer is -3 and 2.

    when you multiply -3 and 2==> -6
    when you add them it equal ==> -1

    so ==> ans= (s-3)(s+2)

    Try to do the same for the other problem.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra II factoring

    I need help. i am having trouble factoring trinomials into binomials. an example problem is 4n^2-5n-6 can someone show me step by step how to factor these kind of problems easily?
  2. math,help,factoring

    i need help i don't know how to do the next step. factor by grouping x^3-3x^2+4x-12 so what i have so far is this =(x^3-3x^2)+(4x-12) =x(x^2-3x)+4(x-3) from here i don't know... and then this one is driving me insane this next one... …
  3. Math

    I have to make up a story problem that divides 4/5 by 2/5 .... I'm having a hard time creating a problem think of having group of friends and food. that one is very common. John used up 4/5 of his gas tank getting 2/5 of the way to …
  4. Math

    I have a question I am having a hard time with..... 2 more than 6 times a number divided 3 Would this be read as (6p / 3) + 2 or 6 (p/3) + 2 thank you for your help!!! Both are correct. In the second one, 6 is equal to 6/1, so when …
  5. Math (Algebra II)

    I'm trying to finish up my summer math packet, and I'm almost done, but I'm having trouble figuring out this one: "Divide and simplify these expressions." (3x^4 - 2x^3 + 16x - 192) / (x^2 - 8) so, that's 3x to the 4th, minus 2x cubed, …
  6. calculus

    I am working on this problem and having some trouble. We're supposed to use partial fractions. The problem is: integral of dx / (x^6-1) . I got the values of A and D, but I am having trouble with the others. Help please!
  7. Algebra

    I am having such a hard time in this class. Hopefully someone here can help me to understand some of what they are trying to teach me. I have a problem here and have been working on it for about an hour now and I can not figure it …
  8. math

    having trouble factoring this particular problem x^2-12x+36-49y2 factored by grouping x(x-12) (7y-6) (7y+6) the answer in the book has (x-6+7y)(x-6-7y) confused.
  9. Mat 117

    •I am having trouble figuring out this question. Why is (3x + 5) (x - 2) + (2x - 3) (x - 2) not in factored form?
  10. math - factoring

    I'm having some trouble factoring a problem. It's 75x^2 - 27 I know I can first factor out a GCF of 3 which leaves me with 3(25x^2 - 9) This seems to me to be a differences of squares but I cannot figure out what to do next. Thank …

More Similar Questions