Find the area of ABC if A=56 degrees, b=20ft, and c=12ft.
1/2(20)(12)sin56
1/2(240)sin56
99.5
To find the area of triangle ABC given angle A, side b, and side c, you can use the formula for the area of a triangle:
Area = 1/2 * b * c * sin(A)
In this case, angle A is 56 degrees, side b is 20 feet, and side c is 12 feet. Plugging these values into the formula, we get:
Area = 1/2 * 20 * 12 * sin(56)
Now, we can calculate this expression:
Area = 1/2 * 240 * sin(56)
To find the value of sin(56), we can use a calculator or reference table. Let's assume that sin(56) is approximately 0.829, but it's always better to use a more accurate value if available.
Area = 1/2 * 240 * 0.829
Simplifying:
Area = 0.5 * 240 * 0.829
Area = 99.5
Therefore, the area of triangle ABC is approximately 99.5 square units.