A red die and a blue die are tossed. What is the probability that the red die shows an odd number and the blue die shows a 1 or 2?
(3/6)*(2/6)= 6/36
answer 1/6
yes
To find the probability that the red die shows an odd number and the blue die shows a 1 or 2, you first need to determine the number of favorable outcomes and the total number of possible outcomes.
For the red die, there are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6). So, the probability of rolling an odd number on the red die is 3/6 or 1/2.
For the blue die, there are two favorable outcomes (rolling a 1 or 2) and six possible outcomes (rolling any number from 1 to 6). Therefore, the probability of rolling a 1 or 2 on the blue die is 2/6 or 1/3.
To find the probability of both events happening together, you multiply the probabilities of each event. So, (1/2) * (1/3) = 1/6.
Therefore, the probability that the red die shows an odd number and the blue die shows a 1 or 2 is 1/6.