Use substitution to solve the linear system.
3x+4y=27
y=x-2
3x+4(x-2)=27
3x+4x-8=27
7x-8=27
7x=35
x=5
y=3
thx
Same as first one except choices i got B is this correct. If not what is it and how do you get this answer?
3x+4y=-11
y=-x-2
A. (-5,1) B.(4,-6) C. (3,-5)
D. No Solution
the answer is C
3x+4(-x-2)=-11
3x-4x-8=-11
-1x-8=-11
-1x=-3
x=3
y= -(3)-2
y=-5
any questions?
Ahhh i miss coulculated.
one more i thank im geting the hang of it now tho.
y=x-2
y=2x
set it up like this
x-2=2x
then x=-2
does y=0
No , y is not zero. It is twice x
To solve the linear system using substitution, we can solve one equation for one variable and substitute it into the other equation.
Let's solve the second equation for y:
y = x - 2
Now we substitute y = x - 2 into the first equation:
3x + 4(x - 2) = 27
Distribute 4 into (x - 2):
3x + 4x - 8 = 27
Combine like terms:
7x - 8 = 27
Add 8 to both sides:
7x = 35
Divide both sides by 7:
x = 5
Now substitute x = 5 back into the second equation to find y:
y = 5 - 2
y = 3
Therefore, the solution to the linear system is x = 5 and y = 3.