It takes 333.51 joules to melt exactly 1 gram of H2O. What is the molar heat of fusion for water, from this data?
1 gram H2O = (1/18.015) mols H2O.
333.51/[1/18.015] =
52
To find the molar heat of fusion for water, we need to first convert the given mass from grams to moles. The molar mass of water (H2O) is approximately 18 g/mol.
1 gram of water is equal to 1/18 moles of water.
Next, we can calculate the molar heat of fusion by dividing the energy required to melt 1 gram of water by the number of moles.
Molar heat of fusion = 333.51 J / (1/18 mol)
Simplifying the above equation:
Molar heat of fusion = 333.51 J * (18 mol/1)
Molar heat of fusion = 6013.18 J/mol
Therefore, the molar heat of fusion for water is approximately 6013.18 J/mol.
To find the molar heat of fusion for water (H2O) using the given data, we first need to convert the mass from grams to moles. Then, we can use the formula:
Molar heat of fusion = Heat required / Moles of substance
1. Let's convert the mass of water from grams to moles. To do this, we need to know the molar mass of water (H2O). The molar mass of H2O is 18.01528 g/mol.
To convert the mass to moles:
Moles of H2O = Mass of H2O / Molar mass of H2O
Moles of H2O = 1 gram / 18.01528 g/mol
2. Now that we have the moles of water, we can calculate the molar heat of fusion.
Molar heat of fusion = Heat required / Moles of H2O
Molar heat of fusion = 333.51 joules / (1 gram / 18.01528 g/mol)
To find the molar heat of fusion, we need to divide 333.51 joules by the value obtained in step 1.
I'll do the calculations for you:
Moles of H2O = 1 gram / 18.01528 g/mol = 0.055497 mol
Molar heat of fusion = 333.51 joules / 0.055497 mol
Calculating this expression gives us:
Molar heat of fusion ≈ 6010.08 joules/mol
Therefore, the molar heat of fusion for water, based on the given data, is approximately 6010.08 joules/mol.