# calculus

posted by .

for each series determine if the series is absolutely convergent and convergent

the sum from 0 to infinity of (-1)^n/(the square root of (n+1))

I did the ratio test and got -1, which is less than 0 making it absolutely convergent, but do i need to take the absolute value of -1? which would then make the test inconclusive?

• calculus -

Yes, you need to take the absolute value of everything, so you get 1 which is inconclusive. If you do the integral test, you find that it diverges.

## Similar Questions

1. ### calculus

determine if the series is absolutely convergent and convergent. the sum from n=0 to infinity of ((-1)^n*e^n)/(n!) I used the ratio test and said that it was absolutely convergent and convergent. is this true?
2. ### calculus

determine if the series is absolutely convergent and convergent. the sum from n=0 to infinity of ((-1)^n*e^n)/(n!) I used the ratio test and said that it was absolutely convergent and convergent. is this true?
3. ### calculus

for the series is absolutely convergent and convergent the series from 1 to infinity of (x^3)/(5^x) i did the ration test and get absolutely convergent and convergent is this correct?
4. ### calculus

for each series determine if the series is absolutely convergent and convergent the sum from 0 to infinity of (-1)^n/(the square root of (n+1))
5. ### calculus

determine if the series is absolutely convergent and convergent the sum from n=1 to infinity of sin(n^2)/n^2 what series test should I use and how?
6. ### calculus

for the series is absolutely convergent and convergent the series from 1 to infinity of (x^3)/(5^x) i did the ration test and get absolutely convergent and convergent is this correct?
7. ### calculus

Is this correct? determine if absolutely convergent and convergent 1. the series from n=0 to infinity of ((-1)^n)/n! I said it was abs. conv, and therefore conv 2. the series from n=0 to infinity of (-1)^n/(the square root of (n^2+n+1))