Algebra II
posted by Jon .
Identify the vertex, axis of symmetry, and direction of opening for y=2(x+3)^25.
vertex = 1/2
axis = 1/2
direction = up

your text should have the following:
for y = a(xp)^2 + q
vertex is (p,q)
axis of symmetry: x=p
opening: up if a>0, down if a<0
please redo your answers and let me know what you got. 
y=2x+3^25
y=2x+95
x=b/2a
x=9/2(9)
x=1/2
I don't know if I have the value for a right 
vertex= (3,5)
axis of symmetry= x=2
direction= up b/c 2>0