Algebra II

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Identify the vertex, axis of symmetry, and direction of opening for y=2(x+3)^2-5.

vertex = 1/2
axis = 1/2
direction = up

  • Algebra II -

    your text should have the following:

    for y = a(x-p)^2 + q

    vertex is (p,q)
    axis of symmetry: x=p
    opening: up if a>0, down if a<0

    please redo your answers and let me know what you got.

  • Algebra II -

    y=2x+3^2-5
    y=2x+9-5

    x=-b/2a
    x=-9/2(-9)
    x=1/2

    I don't know if I have the value for a right

  • Algebra II(I think I got it) -

    vertex= (3,-5)
    axis of symmetry= x=2
    direction= up b/c 2>0

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