Sunday, March 2, 2008 at 11:00am.
Determine the equation of any vertical asymptotes and the value of x for any holes in the graph: f(x)= x^2-11x+18/x-2.
I factored and got: (x-9)(x-2)/x-2
Answer: no vertical asymptotes and x= 2&-7 are the holes.
Is this correct?
The original equation is the same as x-9, but becomes 0/0 with a limiting value of -7 at x=2. There is no vertical asymptote and no singularity "hole?" at x=9.
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