Physics

posted by .

A block oscillates on a spring and passes its equilibrium position with a speed of .157m/s. It's kinetic energy is zero when the block is at the distance of .1m from equilibrium. Assume no friction between the block and the table.

v=.157m/s
KE =0J when x=.1m

a)First I need to find the period of the oscillation:
1/2 mv^2=1/2 k (.1)^2
solve for m/k
m/k=.416

T=2pi*sqrt(m/k)
=2pi*sqrt(.416)
=4.05s

b) what's the mass displacement from the equilibrium when its velocity v=v_mx/2?

Thus wouldn't v_max =2(v) = 2(.157m/s) = .314m/s
V_max=(2pi)/T * x_max
.314m/s=2pi/4.05s * x_max
x_max= .2m

c) what's the spring constant if the restoring force acting on the mass when its velocity v=v_max/2 is 8.67N?

F=kx
8.67N=k(.2m)
k=43.35N/m

d) what's the acceleration of the mass when v=v_max/2?:

i know that F=ma
a=F/m

Given that m/k= .416 and k=43.35N/m to find m would I mulitiply .416 by 43.375. This would give me 18kg.

Finally to solve the problem a=8.67N/18kg= .481m/s

Are these correct?

  • Physics -

    a) I get(.1/.157)^2 = .4057 for m/k
    b) When the velocity is 1/2 the max, KE is 1/4 of the total, so PE is 3/4 of the total. The spring deflection is therefore sqrt(3/4) of the maximum, or
    0.0866 m
    Deflection cannot ever be as much as 0.2 m if it stopped at 0.1 m
    Make the appropriate corrections and see if you can complete the problem.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    a 2.00 kg block is attached to a spring of force constant 500 N/m. The block is pulled 5.00 cm to the right of equilibrium and released from rest. Find the speed of the block as it passes through equilibrium if a) the horizontal surface …
  2. physics

    A moving 1.60 kg block collides with a horizontal spring whose spring constant is 295 N/m. The block compresses the spring a maximum distance of 3.50 cm from its rest position. The coefficient of kinetic friction between the block …
  3. Physics

    A block oscillates on a spring and passes its equilibrium position with a speed of .157m/s. It's kinetic energy is zero when the block is at the distance of .1m from equilibrium. Assume no friction between the block and the table. …
  4. Physics

    A block oscillates on a spring and passes its equilibrium position with a speed of .157m/s. It's kinetic energy is zero when the block is at the distance of .1m from equilibrium. Assume no friction between the block and the table. …
  5. Physics

    A block oscillates on a spring and passes its equilibrium position with a speed of .157m/s. It's kinetic energy is zero when the block is at the distance of .1m from equilibrium. Assume no friction between the block and the table. …
  6. Physics

    A moving 4.80 kg block collides with a horizontal spring whose spring constant is 243 N/m. The block compresses the spring a maximum distance of 5.50 cm from its rest position. The coefficient of kinetic friction between the block …
  7. physics

    A moving 3.20 kg block collides with a horizontal spring whose spring constant is 224 N/m. The block compresses the spring a maximum distance of 5.50 cm from its rest position. The coefficient of kinetic friction between the block …
  8. Physics

    A moving 3.20 kg block collides with a horizontal spring whose spring constant is 224 N/m. The block compresses the spring a maximum distance of 5.50 cm from its rest position. The coefficient of kinetic friction between the block …
  9. Physics

    A moving 3.20 kg block collides with a horizontal spring whose spring constant is 224 N/m. The block compresses the spring a maximum distance of 5.50 cm from its rest position. The coefficient of kinetic friction between the block …
  10. physics

    A block of mass 4kg hangs from a spring of force constant 400N/m.the block is pulled down 15cm below the equilibrium position and released. Fimd: a) amplitude, frequency and period of vibration. b) kinetic energy when the block is …

More Similar Questions