Algebra II
posted by Jon .
Solve 2x^2=3x+2 by graphing. If excat roots cannot be found, state the consecutive integers between which the roots are located.
I don't have an answer but I made a table and plugged in these values for x respectfully: 1/4, 2/4, 3/4, 1, 0
Thats all I have

somehow it's hard to find the roots manually since
b^2  4ac <0 
first of all bring all terms to one side
2x^2  3x  2 = 0
now let f(x) = 2x^2  3x  2
did you notice that it factors?
f(x) = (2x+1)(x2)
so the xintercepts are 1/2 and 2
which then become the roots of the equation from above.
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