Algebra II

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4xy^3/z^2 divided by (8x^2y/z^3)^2

I came up with the following:


Simplified into x^3y/16x^3.

Is this correct?

Thanks for your help earlier and now.

  • Algebra II -

    No. x^3*y/16 = y/16, and that is not the answer.

    You've got a (1/z^2) divided by a (1/z^6), which should be z^4, yet you have no "z" term in your answer.

    Try writing it as
    and then canceling terms.

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