Consider an acid, HA, with pKa =3.33
0.025 moles of hydroxide ion are added to 17.4mL of a 0.519 M solution of the acid. What is the resulting pH?
I know pKa=-log([Ka])
pH=-log([H+])
I don't know how to link this information. Thanks
Write an equation and balance it for the HA acid reacting with hydroxide ion.
Use the mols acid and react with mols base. This will form a salt of the weak acid and the strong base. That will be a buffer. Then use the Henderson-Hasselbalch equation to solve for pH. Do you know the HH equation? If not, there is another way of doing it.