All the even numbers from 2 to 98 inclusive, except those ending in
0, are multiplied together. What is the rightmost digit, that is,
the units digit of the product?
2*4*6*8 = 384, and that last digit "4" will be the last digit of each group of _2,_4,_6,_8 that gets multiplied. After multiplying 10 numbers that end in 4, the last number will be the same as the last digit of 4^10, which is 6.
What two numbers multiplied together equals 5040 and added together equals 98
To find the rightmost digit of the product, we need to multiply all the even numbers from 2 to 98 (excluding those ending in 0) together. Here's how you can approach it step by step:
1. First, let's identify the list of even numbers between 2 and 98, excluding those ending in 0. The numbers that satisfy these conditions are: 2, 4, 6, 8, 12, 14... (continuing in increments of 2, excluding numbers divisible by 10).
2. Next, multiply all these numbers together. We start by multiplying 2 by 4, then multiply the result by 6, and so on, until we multiply by 98.
3. As you continue multiplying, keep track of the rightmost digit of the intermediate products. For example, if you multiply the numbers 2 and 4, you get 8. The rightmost digit of 8 is 8, so you should only consider the rightmost digit for each multiplication.
4. Finally, once you have multiplied all the numbers together, look at the rightmost digit of the final product. That will be the answer to your question.
I hope this explanation helps! Let me know if you have any further questions.