How do I determine the number of grams for the following Substance? 7.8 mol ZnSo4
grams = mols x molar mass
I got 161.47g/mol for ZnSO4
Zn= 65.4094 g/mol
S= 32.065 g/mol
O= 4(15.999 g/mol)
Other than that your method for calculating is correct.
7.8mol ZnSO4 x 161.47g/mol= _________?
Using a calculator on the web I obtained 161.45 g/mol ZnSO4. I don't know it that site has the "latest" changes or not. I'm glad Christina caught that.
To determine the number of grams for a given substance, you need to know its molar mass. The molar mass refers to the mass of one mole of the substance, expressed in grams per mole.
To calculate the molar mass of ZnSO4 (zinc sulfate) you need to sum up the atomic masses of each element in its chemical formula. Here are the atomic masses of the elements involved:
Zinc (Zn): 65.38 g/mol
Sulfur (S): 32.06 g/mol
Oxygen (O): 16.00 g/mol (x 4 due to four oxygen atoms)
Now let's calculate the molar mass of ZnSO4:
Molar mass of ZnSO4 = (65.38 g/mol) + (32.06 g/mol) + (16.00 g/mol x 4)
Molar mass of ZnSO4 = 65.38 g/mol + 32.06 g/mol + 64.00 g/mol
Molar mass of ZnSO4 = 161.44 g/mol
Now that you know the molar mass of ZnSO4 is 161.44 g/mol, you can use this information to calculate the grams of 7.8 moles of ZnSO4:
Grams = Moles x Molar mass
Grams = 7.8 mol x 161.44 g/mol
Grams ≈ 1,259.39 g
Therefore, 7.8 moles of ZnSO4 is approximately equal to 1,259.39 grams.
1molZnSO4= 164.46gZnSO4( the molar mass)
7.8 mol ZnSO4* (164.46gZnSO4/1molZnSO4)
= 1259.388g ZnSO4