if the ratio of oxygen to air is approximately 1 to 5 and the ratio of oxygen to ethyne is 2 to 5, how do i calulate the ratio of air to ethyne?
Write the balanced equation for ethyne reacting with oxygen; I assume that is the 2:5.
Then g oxygen need for the combustion of ethyne x 1/0.2 = ??
OR you need 5 times as much air as oxygen.
what is g
wat is g
I wrote g to stand for grams. So grams of oxygen you need (or tons or kilotons or what have you) x 5 will be g/tons/kilotons/whathaveyou of air you will need to obtain that much oxygen.
To calculate the ratio of air to ethyne, we can make use of the given ratios of oxygen to air and oxygen to ethyne.
First, let's assume that the amount of oxygen is constant in both ratios. This means we can compare the ratios directly.
Given:
Ratio of oxygen to air = 1:5
Ratio of oxygen to ethyne = 2:5
To make the ratio of oxygen the same in both cases, we need to multiply the first ratio by 2. This gives us:
Adjusted ratio of oxygen to air = 2:10 (multiplied both sides by 2)
Now, we can compare the adjusted ratio of oxygen to air with the ratio of oxygen to ethyne:
Adjusted ratio of oxygen to air = 2:10
Ratio of oxygen to ethyne = 2:5
To calculate the ratio of air to ethyne, we need to equate the oxygen parts in both ratios. Since the oxygen parts are already equal, the remaining parts represent air and ethyne.
So, the ratio of air to ethyne is:
Air:Ethyne = 10:5
Simplifying this ratio, we divide both parts by 5:
Air:Ethyne = 2:1
Therefore, the ratio of air to ethyne is 2:1.