# Algebra

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GCF for the group of terms

-42a^4, 7a^5

42a?

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here is my equation that I am struggling with (7-42a)(-3/7) the 3/7 is a fraction. Just multiply -3/7 by each member of the term; i.e., 7(-3/7) - (42a)(-3/7)= -3 + (6a*3) = can you take it from here?
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would the GCD for -42a^2 and 7a^5 be 7a?
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Annabelle and Navene are multiplying (4275)(4372). Annabelle's Work (4275)(4372) = 4^2 + 375 + 2 = 4577 Navene's Work: (4275)(4372) = 42â‹…375â‹…2 = 46710 Is either of them correct?

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