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Write an equation in slope-intercept form for the line that passes through (3,5) and (-2,1).

y2-y1/x2-x1
1-5/-2-3
-4/-5= slope

y=mx+b
y=-4/-5(3)+b
-2=2.4+b
-4.4= y-intercept

y= -4/-5x+4.4 (answer)

  • Math -

    Rewrite the slope as m = 4/5. -4/-5 is the same thing but looks awkward.

    y = (4/5) x + b
    5 = [(4/5)*3] + b
    5 = 12/5 + b
    b = 13/5
    y = (4/5)x + 13/5

  • Math(here's what I did) -

    Ok, we lmow that the slope is 4/5.
    y=mx+b
    y=4/5(3)+b
    -2=2.4+b
    subtract 2.4 from both sides
    -4.4 which is how I got the y-intercept
    y= 4/5x+4.4

    13/5 = 2.6 not 4.4

  • Math -

    In solving for b, you took the x-value from one point (x=3) and, for y, you used the x value from the other point (x=-2) instead of y. You should have used y=5, as I did in my derivation. You have to use the x and y values of one known point to get the line to pass though that point.

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