According to Pew Research, the contact rate (probability of contacting a selected household) in 1997 was 69% and in 2003 was 76%. However, the cooperation rate (proability of someone at the contacted household agreeing to be interviewed) was 58% in 1997 and dropped to 38% in 2003.
a). What is the probablity (in 2003) of obtaining an interview with the next household on the sample list?
Is the answer 1-(.76)(.38)
b). Was it more likely to obtain an interview from a randomly selected household in 1997 or in 2003?
Is the answer to compare 1-(.76)(.38) and 1-(.69)(.58).
a) I belive your answer is the probability of NOT getting an interview. I think the answer is (.76)(.38)
b) adjust accordingly from a)
a). Yes, the probability of obtaining an interview with the next household on the sample list in 2003 would be 1 - (0.76)(0.38) or approximately 0.7108.
b). To determine which year was more likely to obtain an interview from a randomly selected household, we can compare the probabilities calculated in both years. So, we compare 1 - (0.76)(0.38) for 2003 and 1 - (0.69)(0.58) for 1997. Whichever probability is higher would indicate that it was more likely to obtain an interview in that particular year.
a) Yes, the probability of obtaining an interview with the next household on the sample list in 2003 can be calculated as 1 - (0.76)(0.38).
b) To compare the likelihood of obtaining an interview from a randomly selected household in 1997 and 2003, you can compare the probabilities 1 - (0.69)(0.58) and 1 - (0.76)(0.38).
a) Yes, to calculate the probability of obtaining an interview with the next household on the sample list in 2003, you can use the formula:
Probability = 1 - (Contact rate in 2003) x (Cooperation rate in 2003)
So the calculation would be: Probability = 1 - (0.76)(0.38)
b) To determine whether it was more likely to obtain an interview from a randomly selected household in 1997 or 2003, you can compare the probabilities calculated using the formula from part a) for each year.
For 1997: Probability = 1 - (0.69)(0.58)
For 2003: Probability = 1 - (0.76)(0.38)
Compare the two probabilities to see which one is higher. The higher probability indicates a higher likelihood of obtaining an interview from a randomly selected household.