posted by annie .
a) antimony pentafluroide
Sb(-3) + F5(-1) --> SbF4 ?
b) aluminium bromide hexahydrate
Al(-1) + Br(-1) --> AlBr3 . 6H2O ?
The charges don't add up for (b), is there something to do with the "ide"? I don't get it.
And for (a) how did "pentafluoride" end up to be "F4"? --- shouldn't the answer be Sb(F5)3?
Antimony has an electronic structure of
# Ground state electron configuration: [Kr].4d10.5s2.5p3
Which means its valences can be +5, or +3. I don't know of a fluoride SbF4, and suspect one does not exist.
Aluminum has a common valence of +3. Take a look at its electronic structure.