algebra
posted by jimmy .
i need help on these three..thank you...find the real number solutions of the equation..2v^6=16
2h^512=16h
3q^4+3q^3=6q^2+6q

2v^6=16
Are you sure about the  sign?
Any real number to the sixth power is positive, and multiplying it by 2 would require 2v^6 to be negative. The left side could never equal 16.
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