algebra

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i need help on these three..thank you...find the real number solutions of the equation..-2v^6=16

2h^5-12=-16h
3q^4+3q^3=6q^2+6q

  • algebra (#1 of 3) -

    -2v^6=16
    Are you sure about the - sign?
    Any real number to the sixth power is positive, and multiplying it by -2 would require -2v^6 to be negative. The left side could never equal 16.

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