What is the mass of hydrogen produced from the reaction of 2.31 grams of HCl with magnesium?
HCl + Mg2 ---> H2 + MgCl2
4HCl + Mg2 = 2H2 + 2MgCl2
4mol 2mol
2.31gr ?gr
HCl mole = 2.31/(1.008+35.45)=0.06 mol
4HCl/1H2
0.06mol HCl x (1molH2/4molHCl)= 0.015mol H2
mass of H2 = 0.015 x (2*1.0008) =0.03gram H2
i think that's how it works.. plz check your answer
The equation is
Mg + 2HCl ==> H2 + MgCl2
Convert 2.31 g HCl to mols. mols = g/molar mass.
Convert mols HCl to mols H2 using the coefficients in the balanced equation.
Convert mols H2 to grams.
grams = mols H2 x molar mass H2.
Post your work if you get stuck.
To determine the mass of hydrogen produced from the reaction of HCl with magnesium, we need to apply stoichiometry, which is a method of calculating the relationship between reactants and products in a chemical reaction.
The balanced chemical equation for the reaction between HCl and magnesium is:
2HCl + Mg → MgCl2 + H2
From the balanced equation, we can see that 2 moles of HCl react to produce 1 mole of H2.
To find the moles of HCl, we need to convert the given mass of HCl to moles using the molar mass of HCl, which is 36.46 g/mol (1 mole of HCl = 36.46 grams of HCl).
Moles of HCl = (mass of HCl) / (molar mass of HCl)
Moles of HCl = 2.31 g / 36.46 g/mol
Now, since the reaction stoichiometry tells us that 2 moles of HCl produce 1 mole of H2, we can calculate the moles of H2 produced by dividing the moles of HCl by the stoichiometric ratio.
Moles of H2 = (Moles of HCl) / (2 moles of HCl)
Finally, to find the mass of hydrogen produced, we multiply the moles of H2 by the molar mass of hydrogen, which is 2.02 g/mol.
Mass of H2 = (Moles of H2) x (molar mass of H2)
By following these steps, you can determine the mass of hydrogen produced from the reaction.