chemistry

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2Al+3Cl2=2AlCl3
calculate the amount(number) of excess reagen units remaining when 4.03x10^23 Al atoms and 6.42x10^23 Cl2 molecules react?

please help!!!!! thanks

  • chemistry -

    For each Al, one needs 1.5 Cl2

    So, one needs 1.5*4.03E23 or 6.045E23 Cl2.
    Thus, there is an excess of Cl2.

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