Algebra
posted by Jon .
1)If y varies inversely as x and y = 3, when x = 6. Find y when x = 36.
A)72
B)2
C)1/2
D)18
I chose C
y1/x2 = y2/x1
3/36 = y2/6
18/36 = 1/2
2)Write the equation 4^3 = 1/64 in logarithmic form.
A)log64 = 4^3
B)log^3 64 = 4
C)log^4 1/64 = 3
D)log^4(3) = 64
I chose C
3)Solve: 6^n+1 >= 10. Round to four decimal places.
A)n >= 0.2851
B)n >= 0.6667
C)n >= 1.2851
D)n >= 0.7782
I chose C
log10/log6
1.2851

All answers are correct. Good work!
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