# Algebra

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1)If y varies inversely as x and y = 3, when x = 6. Find y when x = 36.

A)72
B)2
C)1/2
D)18
I chose C

y1/x2 = y2/x1
3/36 = y2/6
18/36 = 1/2

2)Write the equation 4^-3 = 1/64 in logarithmic form.

A)log64 = 4^3
B)log^-3 64 = 4
C)log^4 1/64 = -3
D)log^4(-3) = 64
I chose C

3)Solve: 6^n+1 >= 10. Round to four decimal places.
A)n >= 0.2851
B)n >= 0.6667
C)n >= 1.2851
D)n >= -0.7782
I chose C

log10/log6
1.2851

• Algebra -

All answers are correct. Good work!

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