Find a number such that 32 is 60% of the number.(decimal answer rounded to nearest tenth)
53.3
Here is the process:
32 = 60%X = .6X
53.3 = X
Hope this helps a little more. Thanks for asking.
You were given:
Find a number such that 32 is 60% of the number.
NOTE: Decimal answer rounded to nearest tenth.
Let x = number we want to find
The word [of] means to MULTIPLY in math.
The word [is] means EQUAL.
We now have this equation:
32 = 0.60(x)
Divide both sides by 0.60 to find x.
32/0.60 = x
53.3333333, etc = x
We round this decimal to the nearest tenths and we get
53.3 = x
Done!
To find a number such that 32 is 60% of that number, we can set up an equation. Let's call the number we are looking for "x".
We can express "32 is 60% of x" as the equation:
32 = 0.60 * x
To solve for x, we need to isolate it on one side of the equation. To do this, we can divide both sides of the equation by 0.60:
32 / 0.60 = x
Using a calculator, we can simplify the left side of the equation:
32 / 0.60 ≈ 53.33
Therefore, the number we are looking for, rounded to the nearest tenth, is approximately 53.3.