Pre Cal
posted by Kindell .
a ski slope on a mountian has an angle of elevation of 25.2 degrees. the vertical height of the slope is 1808 feet. how long is the slope?

Pre Cal 
Anonymous
This is using your trig function.
sine = opposite/hypotenuse
In this problem, we are finding the hypotenuse. Think of the mountain as a right triangle.
sin(25.2) = 1808/x and you are solving for x. 
Pre Cal 
Kindell
i tried doing that but my hypotenuse was smaller then my opposite... is that ok...
sin(25.2)= .4257 then i divided by 1808 to get x by itself and i got...
2.3535 E 4
wouldn't that be wrong? 
Pre Cal 
Anonymous
No  you should have done 1808/.4257 and get 4246.33.

Pre Cal 
Guido
We use sine = opp/hyp
Let x be the height of the slope that we are seeking.
sin(25.2 degrees) = 1808 feet/x
Multiply both sides by x and we get:
sin(25.2 degrees)(x) = 1808 feet
Next: Divide both sides by sin(25.2 degrees) to find x.
x = 1808 feet/sin(25.2 degrees)
x = ????
Can you finish?
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