A transformer has 50 turns in its primary coil and 250 turns in its secondary coil. 12V is connected to the primary.
a. Find the voltage across the secondary coil.
b. Find the current in a 10 ohm device connected to the secondary.
c. Find the power supplied to the primary.
To answer these questions, we can use the concept of transformer turns ratio. The turns ratio is the ratio of the number of turns in the primary coil to the number of turns in the secondary coil. In this case, the turns ratio is given as 50:250, which simplifies to 1:5.
a. To find the voltage across the secondary coil, we can use the turns ratio. Since the turns ratio is 1:5, this means that if 12V is applied across the primary coil, the voltage across the secondary coil will be 12V multiplied by the turns ratio, which is 12V x 5 = 60V.
b. To find the current in a 10 ohm device connected to the secondary, we can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, the voltage across the secondary coil is 60V as calculated in part a, and the resistance of the device is 10 ohms. Therefore, the current in the device is I = 60V / 10 ohms = 6A.
c. To find the power supplied to the primary, we can use the equation: Power (P) = Voltage (V) x Current (I). In this case, the voltage across the primary coil is 12V, and the current can be calculated using the turns ratio. Since the turns ratio is 1:5, the current in the primary will be the current in the secondary divided by the turns ratio, which is 6A / 5 = 1.2A. Therefore, the power supplied to the primary is P = 12V x 1.2A = 14.4W.
I will be happy to critique your thinking. These questions are straigforward use of formulas.
a. 60V
b. 6A
c. 72W