susy has 22 coins in her pocket totaling $1.80. what combination of coins could she have
*riminder the numbers of coins has to equal 22 but the amount has to equal to 1.80
I believe this is correct...check it though. I just used trial and error.
2 quarters = .50
10 dimes =1.00
5 nickels = .25
5 pennies = .05
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22 coins =1.80
how do you do intergers
To determine the combination of coins that Susy could have, we can start by listing the possible values of each type of coin. Let's assume she only has quarters, dimes, and nickels.
Since the number of coins must equal 22 and the total amount must equal $1.80, we can create two equations:
1. Number of quarters (Q) + Number of dimes (D) + Number of nickels (N) = 22 (Equation 1)
2. Value of quarters in cents (25Q) + Value of dimes in cents (10D) + Value of nickels in cents (5N) = 180 (Equation 2)
To solve this system of equations, we can use a method called trial and error. We will start by assuming different values for the number of each coin until we find a combination that satisfies both equations.
Here are some possible combinations:
1. 8 quarters, 4 dimes, and 10 nickels:
Q = 8, D = 4, N = 10
Equation 1: 8 + 4 + 10 = 22 (correct)
Equation 2: (25 * 8) + (10 * 4) + (5 * 10) = 200 + 40 + 50 = 290 (incorrect)
2. 2 quarters, 16 dimes, and 4 nickels:
Q = 2, D = 16, N = 4
Equation 1: 2 + 16 + 4 = 22 (correct)
Equation 2: (25 * 2) + (10 * 16) + (5 * 4) = 50 + 160 + 20 = 230 (incorrect)
3. 4 quarters, 10 dimes, and 8 nickels:
Q = 4, D = 10, N = 8
Equation 1: 4 + 10 + 8 = 22 (correct)
Equation 2: (25 * 4) + (10 * 10) + (5 * 8) = 100 + 100 + 40 = 240 (incorrect)
By continuing this process, you can find the correct combination. In this case, there are no possible combinations of quarters, dimes, and nickels that satisfy both equations. Therefore, there might be other coin denominations involved or one of the conditions may be incorrect.