THE DIFFERENCE BETWEEN TWO NUMBERS IS 16. FIVE TIMES THE SMALLER IS THE SAME AS 8 LESS THAN THREE TIMES THE LARGER. FIND THE NUMBERS? HOW DO YOU SOLVE THIS? PLEASE.
two numbers: x,y
x-y=16
5y=8-3x
u have to solve this system
HOW DO YOU SOLVE 5Y=8-3X? (BIG HELP)
L1: x-y=16
L2: 5y=8-3x
in L1: x=16+y
so in L2 : 5y=8-3*(16+y)=8-48-3y
so 8y=-40
y=-5
in L1 : x-y=16
x-(-5)=16
x=11
if u don't understand this, u have to read your math lesson
THE PRICE OF A SWEATER IS $5 LESS THAN TWICE THE PRICE OF A SHIRT. IF FOUR SWEATERS AND THREE SHIRTS COST $200, FIND THE PRICE OF EACH SHIRT AND EACH SWEATER? HOW DO YOU SET UP THIS PROBLEM?
x=price of a sweater
y=price of a shirt
the system is: x=2y-5
4x+3y=200
so try to solv the system
To solve this problem, let's break it down into steps:
Step 1: Define the variables
Let's assume that the smaller number is represented by 'x' and the larger number is represented by 'y.'
Step 2: Translate the given information into equations
"The difference between two numbers is 16" can be written as:
y - x = 16 (Equation 1)
"Five times the smaller is the same as 8 less than three times the larger" can be written as:
5x = 3y - 8 (Equation 2)
Step 3: Solve the equations simultaneously
To solve the system of equations, we can use a method called substitution or elimination. Let's use the substitution method in this case.
From Equation 1, we can isolate 'y' by adding 'x' to both sides:
y = x + 16 (Equation 3)
Now, substitute Equation 3 into Equation 2:
5x = 3(x + 16) - 8
Simplify the equation:
5x = 3x + 48 - 8
5x - 3x = 40
2x = 40
Divide both sides by 2:
x = 40 / 2
x = 20
Step 4: Find the value of the larger number, 'y'
Substitute the value of 'x' into Equation 3:
y = 20 + 16
y = 36
So, the two numbers are 20 and 36.