A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds.
how much force was exerted on the Puck?
whats the measurement on force?
Thats all the information i have
To calculate the force exerted on the hockey puck, you can use Newton's second law of motion, which states that force is equal to the mass of an object multiplied by its acceleration.
In this case, the acceleration of the hockey puck can be determined by dividing the change in speed by the time taken. The acceleration (a) is given by:
a = (change in speed) / (time)
The change in speed is given as 6 m/s, and the time is given as 2 seconds. Plugging these values into the formula:
a = 6 m/s / 2 s
a = 3 m/s²
Now that we have the acceleration, we can calculate the force exerted on the hockey puck. The formula for force (F) is:
F = mass × acceleration
The mass of the hockey puck is given as 0.200 kg. Plugging in these values:
F = 0.200 kg × 3 m/s²
F = 0.600 N
Therefore, the force exerted on the hockey puck is 0.600 Newtons.