posted by Anonymous .
A small 2g plastic ball is suspended by a 20 cm long string in a uniform electric field. If the ball is in equilibrium when the string makes a 15 degree angle with the vertical, what is the net charge on the ball? E=10^3 N/c(answer: 5.25x10^-6)
I know E=q/r^2
The answer depends upon the direction of the applied electric field. Is it horizontal?
Let's assume that it is, and that the string tenston force is T. In that case
T cos 15 = M g
T sin 15 = Q E
tan 15 = Q E/(M g) = 0.268
g is the acceleration of gravity and M is the mass.
Solve for Q . Make sure M is in kg
The length of the string does not matter, but the angle does.
ITS LIKE S-O-L-O , S-O-L-O , LIVING MY LIFE AINT GOT STRESS NO MO'
What if the electric field is not horizontal?