A store clerk wants to stack 55 cans of tennis balls in a triangular display. How many cans would be in the bottom row?
answer is 10...i used guess and check ...!
We also got ten, but we trying to explain it to a 9 year old for her schoolwork. That is where we are stuck.
Math is the study of patterns.
My first column is the sum of cans after so many rows,
the second column in the increase in the number of cans
Think of racking up billiard balls
.......О
.....О О
....О О О
...О О О О
..О О О О О
.О О О О О О
О О О О О О О
О О О О О О О О
1
---2
3
---3
6
---4
10
---5
15
---6
21
etc, do you see the pattern?
i need help on fact families 6 and 5 pleaseeeeee answer me
Estimating Products Example 7multiply42 is close to 7 multiply ?
10
the answer i got was 7 tennis balls
There are 8 pencils in a package how many packages will be needed for 28 children if each child gets 4 pencils
To determine the number of cans in the bottom row of a triangular display, we need to find the largest triangular number less than or equal to the total number of cans.
A triangular number is a number that can form an equilateral triangle. The formula for calculating the nth triangular number is given by: Tn = (n * (n + 1)) / 2, where n is the position of the triangular number.
Since the store clerk wants to stack 55 cans, we can start by finding the largest triangular number less than or equal to 55 by trial and error:
T1 = 1 (1 can)
T2 = 3 (1 + 2 = 3 cans)
T3 = 6 (1 + 2 + 3 = 6 cans)
T4 = 10 (1 + 2 + 3 + 4 = 10 cans)
T5 = 15 (1 + 2 + 3 + 4 + 5 = 15 cans)
T6 = 21 (1 + 2 + 3 + 4 + 5 + 6 = 21 cans)
T7 = 28 (1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 cans)
T8 = 36 (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36 cans)
T9 = 45 (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 cans)
T10 = 55 (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 cans)
From the above calculations, we see that T10 is the largest triangular number less than or equal to 55. Therefore, there would be 10 cans in the bottom row of the triangular display.