On a dt graph if there is a curve from 1 decreasing to 1.2 in an interval does is the velocity and acceleration + or 9? And is it slowing down or speeding up or neither?
I don't understand how from 1 to 1.2 is a decrease.
1-1.2 is the time interval and at 1 the point is at 150 and 1.2 the point is at 50.
To determine the velocity and acceleration from a position vs time graph (dt graph), we need to analyze the slope and concavity of the curve.
1. Calculate the velocity:
- The velocity is given by the slope of the dt graph.
- If the curve is decreasing from 1 to 1.2, the slope of the curve would be negative.
- Therefore, the velocity would be -0.2 (decreasing from 1 to 1.2).
2. Calculate the acceleration:
- The acceleration is given by the change in velocity over the change in time.
- Since the velocity is constant (-0.2) over the given interval (since we have a straight decreasing line), the acceleration would be zero (0).
3. Determine whether it's slowing down, speeding up, or neither:
- Since the velocity is negative and decreasing (going from 1 to 1.2), the object is slowing down.
In summary, the velocity is -0.2, the acceleration is 0, and the object is slowing down.