How do u find the Hvap if you only know the slope is -.002 ?
This site tells you how to do it.
http://www.science.uwaterloo.ca/~cchieh/cact/c123/clausius.html
To find the enthalpy of vaporization (Hvap) using only the slope value, you would need additional information. The slope alone does not provide enough data to calculate the enthalpy of vaporization.
The enthalpy of vaporization is the amount of heat required to convert one mole of a substance from the liquid phase to the gas phase at a constant temperature. It is usually given in units of Joules per mole (J/mol).
In order to calculate the enthalpy of vaporization, you need the equation of a plot that relates the vapor pressure of the substance to the temperature. This plot is typically obtained experimentally and is known as the Clausius-Clapeyron equation:
ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1)
In this equation:
- P1 and P2 are the vapor pressures at temperatures T1 and T2, respectively.
- ΔHvap is the enthalpy of vaporization.
- R is the ideal gas constant (8.314 J/(mol·K)).
- T1 and T2 are the corresponding temperatures in Kelvin.
By measuring the vapor pressures and temperatures of the substance at two different points, you can use the equation and rearrange it to solve for ΔHvap:
ΔHvap = -slope * R
But without knowing the exact temperatures and vapor pressures, it is not possible to determine the value of the enthalpy of vaporization (Hvap) with only the slope information.