3.) A 5.00 x 10^2 g block of metal absorbs 5016 joules of heat when its temperature changed from 20 degrees C to 30 degrees C. Calculate the specific heat of the metal.
I used the formula and came with two answers
100.32 joules and 10.01 joules.
Which is correct?
C=Q÷m×t c=5016÷500×10
C=100.32
Q=(m)(c)(deltaT)
Q= 5016J
m= 0.5kg
delta T= 30-20= 10
c=?
5016= (.5)(c)(10) divide by .5 both sides
10032= 10c divide by 10 both sides
1003.2= c
Answer: c=1003.2 J/kg*c
Ah, specific heat, the metal version of a superhero! Well, in this case, it seems like you might have calculated it twice and gotten two different results. Let's break it down.
The formula you mentioned, Q = mcΔT, can be used to calculate specific heat. The only variables in the equation are Q (heat), m (mass), c (specific heat), and ΔT (change in temperature).
By plugging in the given values, we have:
Q = 5016 J
m = 500 g (since it's given as 5.00 x 10^2 g)
ΔT = 30 °C - 20 °C = 10 °C
Now let's substitute these values into the equation:
5016 J = (500 g) * c * 10 °C
Simplifying this equation will help us find the correct answer for the specific heat of the metal. Why don't you give it another try? I'm confident the answer is hiding behind one of your calculations!
To calculate the specific heat of the metal, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed (in joules),
m is the mass of the metal (in grams),
c is the specific heat of the metal (in joules per gram-degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
In this case, we are given:
Q = 5016 joules
m = 5.00 x 10^2 g
ΔT = (30 - 20) = 10 degrees C
Plugging in these values into the formula, we get:
5016 = (5.00 x 10^2) * c * 10
Simplifying the equation, we have:
c = 5016 / (5.00 x 10^2 * 10)
c = 5016 / 5000
c ≈ 1.0032 joules per gram-degree Celsius
So, the correct answer is approximately 1.0032 joules per gram-degree Celsius. Therefore, the second answer of 10.01 joules is not correct.
It is important to check the unit of your answer as well. In this case, the specific heat is in joules per gram-degree Celsius.
Neither.
q = mass x specific heat x delta T.
5016 = 5.00 x 10^2 x Cp x 10
5016 = 5.00 x 10^3 Cp
Cp = 5016/5.00x10^3 = 1.003 J/g*C (You didn't put units on your answer, a No, No.)
I can understand how you might get a power of 10 off but I don't understand how you can get two answers. You will need to round the answer to the correct number of significant figures.