Complete ordered pairs for y=4x+12

(_,0), (3/4,_), (0,_), (-3/4,_)

(0,-3) for the third one if i'm doing it right...

(12,0) for the first
don't know about the other two

in the ordered pair, the first number is always the x, the second is always the y

so for the first one, y = 0
0 = 4x + 12
-12 = 4x
-3 = x

so your first one is (-3,0)

for the second:

y = 4(3/4) + 12
y = 3 + 12
y = 15, so the point is (3/4,15)

do the last one the same way, you should get (-3/4,9)

btw, the third is (0,12)

To find the ordered pairs, you need to substitute the given values into the equation y = 4x + 12 and solve for the missing values.

For the first pair, (_, 0), you are given the y-coordinate as 0. Substitute this value into the equation:

0 = 4x + 12

Now solve for x. To isolate x, subtract 12 from both sides:

0 - 12 = 4x

-12 = 4x

Divide both sides by 4:

-12/4 = x

-3 = x

Therefore, the first ordered pair is (-3, 0).

For the second pair, (3/4, _), you are given the x-coordinate as 3/4. Substitute this value into the equation:

y = 4(3/4) + 12

Simplify:

y = 3 + 12

y = 15

Therefore, the second ordered pair is (3/4, 15).

For the third pair, (0, _), you are given the x-coordinate as 0. Substitute this value into the equation:

y = 4(0) + 12

Simplify:

y = 0 + 12

y = 12

Therefore, the third ordered pair is (0, 12).

For the fourth pair, (-3/4, _), you are given the x-coordinate as -3/4. Substitute this value into the equation:

y = 4(-3/4) + 12

Simplify:

y = -3 + 12

y = 9

Therefore, the fourth ordered pair is (-3/4, 9).

The complete ordered pairs for the equation y = 4x + 12 are (-3, 0), (3/4, 15), (0, 12), and (-3/4, 9).