Multiply
(7-2x^4)^2
Is this right?
36(-2x^4+7)
woops. this one, if I'm seeing it right...
you would have (7-2x^4)(7-2x^4), and then you have to use the "FOIL" method...right?
So, would the answer be
-2x^4+7^2
(7-2x^4)(7-2x^4)
first, multiply the first two: 7x7=49
then, multiply the outside two:7 x -2x^4, which is -14x^4.
then, multiply the inside two, which is also -14x^4
then, multiply the last two:
(-2x^4) x (-2x^4) which is 4x^8.
so, we have: 49 -14x^4 -14x^4 + 4x^8.
simplified to 49 -28x^4 + 4x^8.
To verify if your expression is correct, we need to expand the given expression, (7-2x^4)^2.
To do this, we will use the formula for expanding a binomial squared, which is (a - b)^2 = a^2 - 2ab + b^2.
In this case, a = 7 and b = 2x^4. Substituting these values into the formula, we get:
(7 - 2x^4)^2 = (7)^2 - 2(7)(2x^4) + (2x^4)^2
Simplifying further:
= 49 - 14x^4 + 4x^8
Therefore, your expression should be:
49 - 14x^4 + 4x^8
This means that 36(-2x^4 + 7) is not equal to (7 - 2x^4)^2.