Damien sets up a bucket to catch raindrops. The bucket can hold only 1 gallon. If each raindrop is made up of about 1/90 fluid ounceof water, how many raindrops will the bucket be able to hold?

I need help with this question. I know that 1 gallon=128 fluid ounces. I need a formula to answer.

Let x = number of raindrops.

x = 128 * 90

24!!!

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To solve this problem, you can set up a proportion using the given conversion factor: 1 gallon = 128 fluid ounces.

Let "x" represent the number of raindrops the bucket can hold. We can assume that each raindrop is approximately 1/90 fluid ounce.

So, the proportion can be set up as:

1 gallon / 128 fluid ounces = x raindrops / 1/90 fluid ounces

To solve for "x," we can cross-multiply and then solve for "x."

1 gallon * (1/90 fluid ounces) = 128 fluid ounces * x raindrops

1/90 gallon fluid ounces = 128x raindrops

Now, we need to isolate "x" by multiplying both sides of the equation by 90:

1/90 gallon fluid ounces * 90 = 128x raindrops * 90

1 gallon = 11520x raindrops

Finally, divide both sides of the equation by 11520:

1 gallon / 11520 = 11520x raindrops / 11520

1/11520 gallon = x raindrops

Therefore, the bucket will be able to hold approximately 1/11520 gallon of raindrops.