ax+x<0
ax+x<0
(a+1)x<0
right for : x<0 or a+1<0
mchi t7awaw la ma3raft ta9alwa
To solve the inequality ax + x < 0, you can rearrange the expression by factoring out x as a common term:
x(a + 1) < 0
Now, we have two cases to consider:
Case 1: (a + 1) > 0
If a + 1 is positive, then x must be negative to satisfy the inequality. In this case, the solution is x < 0.
Case 2: (a + 1) < 0
If a + 1 is negative, then x must be positive to satisfy the inequality. In this case, the solution is x > 0.
Therefore, the solution to the inequality ax + x < 0 depends on the value of (a + 1):
- If (a + 1) > 0, then the solution is x < 0.
- If (a + 1) < 0, then the solution is x > 0.