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A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 . Find the value of y

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    The slope of the second line must be 13/5, so that the product of slopes is -1.

    Since the slope is (y2 - y1)/(x2 - x1) for any two points on a line,
    (y+1)/(-1 +6) = 13/5
    (y+1)/5 = 13/5

    Solve for y

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