Northern Maywood voted 60% to 40% in favor of a water project. Southern Maywood voted 90% to 10% against the prject. The project passed 55% to 45%. If 5900 people voted, how many were from Southern Maywood.
Let X be the number of votes cast in S.Maywood. Then 5900-X were cast in N. Maywood. The total number of yes votes was 0.55*5900 = 3245
0.1X + 0.6(5900-X) = 3245
-0.5X = 3245 - 3540 = -295
One more step and you are there.
what is the answer though?
To solve this problem, we'll first find out how many people from Northern Maywood voted in favor of the water project and against it.
Let's assume the total number of people from Northern Maywood who voted is N. Since 60% voted in favor of the project, we can represent this as 0.60N. Similarly, 40% voted against the project, which can be represented as 0.40N.
Next, we'll find out the number of people from Southern Maywood who voted against the project. Let's assume the total number of people from Southern Maywood who voted is S. Since 90% voted against the project, we can represent this as 0.90S.
According to the given information, the project passed with a vote of 55% in favor and 45% against. So, we can represent this as 0.55 * 5900 in favor and 0.45 * 5900 against.
Now we can set up the following equation to solve for S:
(0.45 * 5900) = 0.90S
To solve this equation, multiply 0.45 and 5900 to get the number of votes against the project. Then, divide the result by 0.90 to find the number of people who voted from Southern Maywood:
(0.45 * 5900) / 0.90 = 50S
(2655) / 0.90 = 50S
2949.44 = 50S
Finally, divide both sides of the equation by 50 to solve for S:
S = 2949.44 / 50
S = 58.9888
Since we cannot have a fraction of a person, the number of people from Southern Maywood who voted against the project is approximately 59 people.