Algebra1
posted by Jacob .
A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

Did they leave at the same time?

They could not have left at the same time. Jacobyou left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1  delay) 
no the second one left a half an hour later sorry i forgot to include that

then
564 *t = 744 * (t  .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour 
564t=744(t.5)
564t=744t372
564t564t=744t372564t
0=180t372
0+372=180t372+372
372=180t
372/180=180t/180
2.07=t
Is that correct? 
Yes

But remember to subtract half hour for second plane

ok thank you for all of your help

564*2.07=744*2.07.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?
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