2 cakes are divided into 10 = pieces! there is a ring in one of the 10 slices in each cake. what is the probability that there is no ring in the first slice that you take in both cakes?
Okay Sis, I think this is how you do it. The probability of NOT getting the ring in the first piece of the first cake is 9/10, and the probability of NOT getting it in the first piece of the second piece is also 9/10. I believe you multiply .9 by .9 to find your answer. However, I'm not 100% sure that is how you go about doing it. Perhaps someone else can input their knowledge on this as well. Good luck Mackenzie!
The probability is one of 10 or 1/10.
THANKS BIG SIS! YOU GOT THE RIGHT ANSWER!!!!!!!!!!!!!!!!
To find the probability that there is no ring in the first slice taken in both cakes, we need to first calculate the probability that there is no ring in the first slice of a single cake.
Let's break down the problem:
- Each cake is divided into 10 slices, so for each cake, there is a 1 in 10 chance of finding the ring in any given slice.
- Therefore, there is a 9 in 10 chance of not finding the ring in any given slice of a single cake.
To find the probability of not finding the ring in the first slice of both cakes, we multiply the probabilities together because the events are independent (the outcome of one cake does not affect the outcome of the other cake).
So the probability of not finding the ring in the first slice of both cakes is:
(9/10) * (9/10) = 81/100 or 0.81
Therefore, the probability that there is no ring in the first slice taken in both cakes is 0.81 or 81%.