How many grams do you need to make 100 mL of a 0.1 M buffer?
I got .01 grams. Is that right? If not, will you show me the right answer and how you got it?
Thanks.
What pH? What materials? There is no way to answer with the information given.
To determine the number of grams needed to make a 100 mL solution of a 0.1 M buffer, you will need to know the molar mass of the buffer compound. Here's the step-by-step process:
1. Firstly, calculate the number of moles required using the molarity and volume of the solution:
moles = molarity × volume
moles = 0.1 M × 0.1 L (since 100 mL = 0.1 L)
moles = 0.01 mol
2. Next, you need to convert moles to grams using the molar mass of the buffer compound. Assume the molar mass is M gram/mol (replace "M" with the actual value):
grams = moles × molar mass
grams = 0.01 mol × M gram/mol
grams = 0.01M g
Given that you have found the molar mass M, substitute it into the equation. Only then can we calculate the correct number of grams required.
Please provide the molar mass of the buffer compound so that I can help you find the accurate answer.