Today, Daryl is two-thirds as old as he will be eight years before

he is twice as old as he is now. How many years old is Daryl today?

This is not calculus,it is beginning algebra. What is the point of labeling it calculus?

Let x be his age now.

(2/3)(2x- 8) = x
x/3 = 16/3
x = 16

okay begnning algebra do u know how to do it??

To find Daryl's age, let's start by breaking down the given information:

1. "Daryl is two-thirds as old as he will be eight years before he is twice as old as he is now."

Let's assume Daryl's current age is "x" years. According to the given information, eight years before Daryl is twice as old as he is now, he will be "2x" years old. Therefore, his age eight years before will be "2x - 8" years.

Next, we are told that Daryl's age today is two-thirds of his age eight years before. So, we can write an equation based on the information:

x = (2/3)(2x - 8)

Now, let's solve the equation to find Daryl's age.

Step 1: Distribute (2/3) on the right side of the equation.

x = (4/3)x - (16/3)

Step 2: Subtract (4/3)x from both sides to isolate x.

x - (4/3)x = - (16/3)

Step 3: Find a common denominator for x and (4/3)x, which is 3.

(3/3)x - (4/3)x = - (16/3)

Step 4: Simplify the left side.

-(1/3)x = - (16/3)

Step 5: Multiply both sides by -3 to get rid of the negative sign on the left side.

(1/3)x = 16/3

Step 6: Multiply both sides by 3 to isolate x.

x = (16/3) * 3

Step 7: Simplify.

x = 16

Therefore, Daryl is 16 years old today.