Calculus
posted by Anonymous .
Find the average value over the given interval.
y=3x^5; [3,3]
I can't seem to get the answer, 0.
1/(3+3) [integral 3 to 3 (3x^5)dx]
and I get 273/2

Calculus 
Anonymous
I took the antiderivative incorrectly. I figured out my mistake.
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