# Algebra

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(8(x^3y^4)2)-2

• Algebra -

Are the last 2's exponents? That would mean you want to know
[8(x^3y^4)^2]^-2
The +2 and -2 operations on (x^3y^4) would leave it unchanged, and leave you with
(1/64)(x^3y^4)

• Algebra -

The 2's are not exponents

• Algebra -

Apologies to you and James B, I'm home from work now and just looked at the problem and the 2's are exponents.

• Algebra -

The problem to solve is:
(8(x^3y^4)2)-2

Multiply 8 and
8*(x^3*y^4)2 evaluates to 64

Abort (8*(x^3*y^4)2)-2 evaluates to 64-64

• Algebra -

Apologies, I'm home from work now and was able to look at the problem for myself and the 2's are exponents.

• Algebra -

If the 2's are exponents, I stand by my original answer.

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