Calculus III

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Derivative of Inverse Trigonometric Functions

f(x) = cos(arcsin(2x))

What is f'(x)?

  • Calculus III -

    I did this down below, after the one drwls answered

  • Calculus III -


    It is so similar that you should be able to do it the same way. Draw the triangle and you have sqrt(1-4x^2)
    f(x) = (1-4x^2)^.5
    f'(x) = .5 [(1-4x^2)^-.5] (-8x)
    = -4x/sqrt(1-4x^2)

  • Calculus III -


    But the text book I'm using gives me the answer:


    No denominators or anything.

  • Calculus III -

    That is just the first step.

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