posted by Sean .
Derivative of Inverse Trigonometric Functions
f(x) = cos(arcsin(2x))
What is f'(x)?
I did this down below, after the one drwls answered
It is so similar that you should be able to do it the same way. Draw the triangle and you have sqrt(1-4x^2)
f(x) = (1-4x^2)^.5
f'(x) = .5 [(1-4x^2)^-.5] (-8x)
But the text book I'm using gives me the answer:
No denominators or anything.
That is just the first step.